GROUP BY having MAX date

Question

I have problem when executing this code:

SELECT * FROM tblpm n  WHERE date_updated=(SELECT MAX(date_updated)  FROM tblpm GROUP BY control_number  HAVING control_number=n.control_number) 

Basically, I want to return the most recent date for each control number. The query above returns correct output but it takes 37secs. before the output was shown.

Is there any other sql clause or command that can execute faster than the query above?

Thanks in advance.

Answer 1

Putting the subquery in the WHERE clause and restricting it to n.control_number means it runs the subquery many times. This is called a correlated subquery, and it's often a performance killer.

It's better to run the subquery once, in the FROM clause, to get the max date per control number.

SELECT n.*  FROM tblpm n  INNER JOIN (   SELECT control_number, MAX(date_updated) AS date_updated   FROM tblpm GROUP BY control_number ) AS max USING (control_number, date_updated); 

Answer 2

There's no need to group in that subquery... a where clause would suffice:

SELECT * FROM tblpm n WHERE date_updated=(SELECT MAX(date_updated)     FROM tblpm WHERE control_number=n.control_number) 

Also, do you have an index on the 'date_updated' column? That would certainly help.