I am trying to learn Go, and I found a good resource here.
The example given on method overloading is reproduced below:
package main import "fmt" type Human struct { name string age int phone string } type Employee struct { Human company string } func (h *Human) SayHi() { fmt.Printf("Hi, I am %s you can call me on %s\n", h.name, h.phone) } func (e *Employee) SayHi() { fmt.Printf("Hi, I am %s, I work at %s. Call me on %s\n", e.name, e.company, e.phone) //Yes you can split into 2 lines here. } func main() { sam := Employee{Human{"Sam", 45, "111-888-XXXX"}, "Golang Inc"} sam.SayHi() }
Is it possible to call the "base" struct's (Human's) methods, eg. sam.Human.SayHi() Downcasting doesn't work (because there is no type hierarchy right?)
You can access the embedded struct of a parent struct by calling the member of the parent with the name of the embedded type's name. That's a mouthful, so it's probably easier to demonstrate it.
sam := Employee{Human{"Sam", 45, "111-888-XXXX"}, "Golang Inc"} sam.SayHi() // calls Employee.SayHi sam.Human.SayHi() // calls Human.SayHi
Outputs
Hi, I am Sam, I work at Golang Inc. Call me on 111-888-XXXX Hi, I am Sam you can call me on 111-888-XXXX
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