Go - What is the equivalent of Python's "pass"?

Question

I have a default cause in a select statement that I want to do nothing, just continue, but leaving the line blank stops anything in the statement from happening

        select {
        case quit_status := <-quit:
            if quit_status == true {
                fmt.Printf("********************* GOROUTINE [%d] Received QUIT MSG\n", id)
                return
            }
        default:
            fmt.Printf("GOROUTINE [%d] step: %d, NO QUIT MSG\n", id, i)
        }

Answer 1

The default case in a select statement is intended to provide non-blocking I/O for channel reads and writes. The code in the default case is executed whenever none of the channels in any of the cases are ready to be read/written to.

So in your case, the default block is executed if the quit channel has nothing to say. You can simply remove the default case and it will block on the quit_status := <-quit case until a value is available in quit.. which is probably what you are after in this instance.

If you want to immediately continue executing code after the select statement, you should run this select statement in a separate goroutine:

go func() {
    select {
    case quit_status := <-quit:
        ...

    }
}()

// Execution continues here immediately.

Answer 2

As @StephenWeinberg pointed out, there is no pass statement in go. Simply put nothing in the case when the channel hits something.

select {
    case <-ch:
        // do something
    case <-time.After(2*time.Second):
        // timeout
    default:
        // do nothing aka pass
}