Given the support code:
{-# LANGUAGE ExtendedDefaultRules, DeriveDataTypeable #-}
{-# LANGUAGE FlexibleInstances, UndecidableInstances, OverlappingInstances #-}
import Data.Typeable
default(A)
data A = A deriving (Eq,Show,Typeable)
class Show a => Testable2 a where
instance (Show a, Eq a) => Testable2 a where
instance (Show a, Testable2 b) => Testable2 (a -> b) where
instance (Show a, Show b) => Show (a -> b) where show _ = "<func>"
test :: (Show p, Typeable p, Testable2 p) => p -> IO ()
test = print . typeOf
In GHC 7.6, I can write:
main = test (\f -> (f $))
And that type checks, and prints:
(A -> A) -> A -> A
However, in GHC 7.8 I get:
Main.hs:
No instance for (Eq (a0 -> b0)) arising from a use of `test'
But, if I refactor to:
main = let ff = \f -> (f $) in test ff
Then it works properly in both GHC 7.8 and GHC 7.6. Why?
The logic behind the support code is an instance for Show (a -> b)
with Show
context to force type defaulting, then a way of handling default atoms (with Eq
), and a way of moving something back over an ->
for Testable2
. The code is designed to allow variable-arity QuickCheck properties, and is taken from hlint.
It seems that test (\ x -> x)
does not even compile with GHC 7.6.3. On the other hand:
($$) = ($)
main = test (\ f -> (f $$))
compiles with both. I suspect defaulting not taking place for ungeneralized/monomorphic type variables in combination with special built-in treatment of ($)
.
Copied from users kosmikus' comment to the question.
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