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In my XML I have the following:
<a>
<b>
<c something="false">
<d>
<e>
<f>someResult</f>
</e>
</d>
</c>
</b>
</a>
Now in the XSL within a loop I can do the following:
<xsl:value-of select="f"></xsl:value-of>
But how can I get the attribute in c?
I've tried doing the following
<xsl:value-of select="////@something"></xsl:value-of>
As well as trying parent and nothing seems to be working. Can you get parent nodes like this?
Also, I cannot just do:
<xsl:value-of select="/a/b/c/@something"></xsl:value-of>
As there can be multiple of c.
779
A Parent of a context node is selected Flat element. A string of elements is normally separated by a slash in an XPath statement. You can pick the parent element by inserting two periods “..” where an element would typically be. The parent of the element to the left of the double period will be selected.
The xsl:attribute element is used to add an attribute value to an xsl:element element or literal result element, or to an element created using xsl:copy. The attribute must be output immediately after the element, with no intervening character data.
XSLT string length is defined as a string function and takes a single string argument and returns an integer value representing the number of characters in the string. It converts any declared type into a string except that an empty parenthesis cannot be converted. The whitespaces are taken into the count.
<? xml version="1.0" encoding="UTF-8"?>
To move up the tree you use ".." per level ie in this instance probably
select="../../../@something" You can also select an ancestor node by name (approx)
select="ancestor::c[1]/@something" See http://www.stackoverflow.com/questions/3672992 for further examples
197
Use:
ancestor::c[1]/@something This selects the attribute named something of the first (from the current node upwards) ancestor named c.
44
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