Getting the last word of an NSString

Question

As the title suggests, I would like to get the last word out of an NSString. I thought using this code:

NSArray *listItems = [someNSStringHere componentsSeparatedByString:@" "];
NSString *lastWordString = [NSString stringWithFormat:@"%@", listItems.lastObject];
anotherNSStringHere = lastWordString;

But I think the NSArray will take a time to load if it's big (and it is big), and it wouldn't recognize a word separated by a comma.

Thanks for helping!

Answer 1

If you want to be super-robust:

__block NSString *lastWord = nil;

[someNSStringHere enumerateSubstringsInRange:NSMakeRange(0, [someNSStringHere length]) options:NSStringEnumerationByWords | NSStringEnumerationReverse usingBlock:^(NSString *substring, NSRange subrange, NSRange enclosingRange, BOOL *stop) {
    lastWord = substring;
    *stop = YES;
}];

(This should also work with non-Roman languages; iOS 4+/OS X 10.6+.)

Basic explanation:

-enumerateSubstringsInRage:options:usingBlock: does what it says on the tin: it enumerates substrings, which are defined by what you pass in as the options. NSStringEnumerationByWords says "I want words given to me", and NSStringEnumerationReverse says "start at the end of the string instead of the beginning".

Since we're starting from the end, the first word given to us in substring will be the last word in the string, so we set lastWord to that, and then set the BOOL pointed to by stop to YES, so the enumeration stops right away.

lastWord is of course defined as __block so we can set it inside the block and see it outside, and it's initialized to nil so if the string has no words (e.g., if it's empty or is all punctuation) we don't crash when we try to use lastWord.

Answer 2

Give this a try:

NSRange range = [someNSStringHere rangeOfString:@" " options:NSBackwardsSearch];
NSString *result = [someNSStringHere substringFromIndex:range.location+1];