Getting the current time as a YYYY-MM-DD-HH-MM-SS string

Question

I'm trying to get the current time as a "YYYY-MM-DD-HH-MM-SS" formatted string in an elegant way. I can take the current time in ISO format from Boost's "Date Time" library, but it has other delimiting strings which won't work for me (I'm using this in a filename). Of course I can just replace the delimiting strings, but have a feeling that there's a nicer way to do this with date-time's formatting options. Is there such a way, and if so, how can I use it?

Answer 1

Use std::strftime, it is standard C++.

#include <cstdio> #include <ctime>  int main () {     std::time_t rawtime;     std::tm* timeinfo;     char buffer [80];      std::time(&rawtime);     timeinfo = std::localtime(&rawtime);      std::strftime(buffer,80,"%Y-%m-%d-%H-%M-%S",timeinfo);     std::puts(buffer);      return 0; } 

Answer 2

The answer depends on what you mean by get and take. If you are trying to output a formatted time string, use strftime(). If you are trying to parse a text string into a binary format, use strptime().