Getting only Month and Year from SQL DATE

Question

As well as the suggestions given already, there is one other possiblity I can infer from your question:
- You still want the result to be a date
- But you want to 'discard' the Days, Hours, etc
- Leaving a year/month only date field

SELECT
   DATEADD(MONTH, DATEDIFF(MONTH, 0, <dateField>), 0) AS [year_month_date_field]
FROM
   <your_table>

This gets the number of whole months from a base date (0) and then adds them to that base date. Thus rounding Down to the month in which the date is in.

NOTE: In SQL Server 2008, You will still have the TIME attached as 00:00:00.000 This is not exactly the same as "removing" any notation of day and time altogether. Also the DAY set to the first. e.g. 2009-10-01 00:00:00.000

select month(dateField), year(dateField)

SELECT convert(varchar(7), getdate(), 126) 

You might wanna check out this website: http://anubhavg.wordpress.com/2009/06/11/how-to-format-datetime-date-in-sql-server-2005/

SELECT DATEPART(yy, DateVal)
SELECT DATEPART(MM, DateVal)
SELECT DATENAME(MM, DateVal)

datename(m,column)+' '+cast(datepart(yyyy,column) as varchar) as MonthYear

the output will look like: 'December 2013'