I'm trying to get a String of a date in Java in the format specified in HTTP 1.1. Which, as far as I can tell, is:
Fri, 31 Dec 1999 23:59:59 GMT
With the time always being GMT.
What would be the easiest way to get this from Date/Calendar/?
Java SimpleDateFormat with Locale String pattern = "EEEEE MMMMM yyyy HH:mm:ss. SSSZ"; SimpleDateFormat simpleDateFormat =new SimpleDateFormat(pattern, new Locale("fr", "FR")); String date = simpleDateFormat. format(new Date()); System.
Formatting DatesString pattern = "yyyy-MM-dd"; SimpleDateFormat simpleDateFormat = new SimpleDateFormat(pattern); String date = simpleDateFormat. format(new Date()); System. out. println(date);
Creating A Simple Date Format A SimpleDateFormat is a concrete class for formatting and parsing dates in a locale-sensitive manner. String pattern = "yyyy-MM-dd" ; SimpleDateFormat simpleDateFormat = new SimpleDateFormat(pattern); The specified parameter “pattern” is the pattern used for formatting and parsing dates.
EDIT:
DateTimeFormatter.ofPattern("EEE, dd MMM yyyy HH:mm:ss z", Locale.ENGLISH).withZone(ZoneId.of("GMT"))
is the way to do it with pure java.time. HTTP 1.1 is to not a 100% match with RFC 1123, so using the java.time.format.DateTimeFormatter.RFC_1123_DATE_TIME formatter will fail for day-of-month less than 10. (thanks to @PavanKamar and @ankon for pointing that out)
Note: to be backwards compliant, you would need to also support the other two formats specified by RFC 2616
In case someone else will try to find the answer here (like I did) here's what will do the trick:
String getServerTime() {
Calendar calendar = Calendar.getInstance();
SimpleDateFormat dateFormat = new SimpleDateFormat(
"EEE, dd MMM yyyy HH:mm:ss z", Locale.US);
dateFormat.setTimeZone(TimeZone.getTimeZone("GMT"));
return dateFormat.format(calendar.getTime());
}
in order to set the server to speak English and give time in GMT timezone.
If you're using Joda-Time (which I would highly recommend for any handling of dates and times in Java), you can do:
import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;
...
private static final DateTimeFormatter RFC1123_DATE_TIME_FORMATTER =
DateTimeFormat.forPattern("EEE, dd MMM yyyy HH:mm:ss 'GMT'")
.withZoneUTC().withLocale(Locale.US);
...
RFC1123_DATE_TIME_FORMATTER.print(new DateTime())
Some applications require the format to include a two digit day-of-month as per RFC7231. The Java 8 DateTimeFormatter.RFC_1123_DATE_TIME
uses a single digit:
System.out.println(DateTimeFormatter.RFC_1123_DATE_TIME.format(ZonedDateTime.now(ZoneOffset.UTC)));
Output: Wed, 1 Aug 2018 14:56:46 GMT
Some applications don't like that. Before you use the old answers that use Joda-time or a pre-java8 SimpleDateFormat
, here's a working Java-8 DateTimeFormatter
:
DateTimeFormatter.ofPattern("EEE, dd MMM yyyy HH:mm:ss O")
Now, when you do this:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE, dd MMM yyyy HH:mm:ss O");
System.out.println(formatter.format(ZonedDateTime.now(ZoneOffset.UTC)));
You get Wed, 01 Aug 2018 14:56:46 GMT
- note the leading zero in the day-of-month field.
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