I want to change a values in byte array to put a long timestamp value in in the MSBs. Can someone tell me whats the best way to do it. I do not want to insert values bit-by-bit which I believe is very inefficient.
long time = System.currentTimeMillis();
Long timeStamp = new Long(time);
byte[] bArray = new byte[128];
What I want is something like:
byte[0-63] = timeStamp.byteValue();
Is something like this possible . What is the best way to edit/insert values in this byte array. since byte is a primitive I dont think there are some direct implementations I can make use of?
Edit:
It seems that System.currentTimeMillis()
is faster than Calendar.getTimeInMillis()
, so replacing the above code by it.Please correct me if wrong.
The BigInteger class has a longValue() method to convert a byte array to a long value: long value = new BigInteger(bytes). longValue();
The String class provides three overloaded getBytes methods to encode a String into a byte array: getBytes() – encodes using platform's default charset. getBytes (String charsetName) – encodes using the named charset. getBytes (Charset charset) – encodes using the provided charset.
Split Byte Array In Java, we can use ByteBuffer or System. arraycopy to split a single byte array into multiple byte arrays. For example, this 000102030a0b0c0d1a1b1c1d2f2f is a byte array (14 bytes) in hex representation, it is a combined of cipher (8 bytes) + nonce (4 bytes) + extra (2 bytes).
There are multiple ways to do it:
Use a ByteBuffer
(best option - concise and easy to read):
byte[] bytes = ByteBuffer.allocate(Long.SIZE / Byte.SIZE).putLong(someLong).array();
You can also use DataOutputStream
(more verbose):
ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
dos.writeLong(someLong);
dos.close();
byte[] longBytes = baos.toByteArray();
Finally, you can do this manually (taken from the LongSerializer
in Hector's code) (harder to read):
byte[] b = new byte[8];
for (int i = 0; i < size; ++i) {
b[i] = (byte) (l >> (size - i - 1 << 3));
}
Then you can append these bytes to your existing array by a simple loop:
// change this, if you want your long to start from
// a different position in the array
int start = 0;
for (int i = 0; i < longBytes.length; i ++) {
bytes[start + i] = longBytes[i];
}
If you want to really get under the hood...
public byte[] longToByteArray(long value) {
return new byte[] {
(byte) (value >> 56),
(byte) (value >> 48),
(byte) (value >> 40),
(byte) (value >> 32),
(byte) (value >> 24),
(byte) (value >> 16),
(byte) (value >> 8),
(byte) value
};
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With