Getting column number of cell with particular text using vba

Question

Hi i need to get column of a cell with the text as ACTION.

My current code is as below.

Option Explicit
Private Sub Worksheet_Change(ByVal Target As Range)
Dim rngDV As Range
Dim oldVal As String
Dim newVal As String
Dim actionColName As String
If Target.Count > 1 Then GoTo exitHandler

On Error Resume Next
Set rngDV = Cells.SpecialCells(xlCellTypeAllValidation)
On Error GoTo exitHandler

If rngDV Is Nothing Then GoTo exitHandler

If Intersect(Target, rngDV) Is Nothing Then
   'do nothing
Else
  Application.EnableEvents = False
  newVal = Target.Value
  Application.Undo
  oldVal = Target.Value
  Target.Value = newVal
  If Target.Column = 3 Then
    If oldVal = "" Then
      'do nothing
      Else
      If newVal = "" Then
      'do nothing
      Else
      Target.Value = oldVal _
        & "+ " & newVal
      End If
    End If
  End If
End If

exitHandler:
  Application.EnableEvents = True
End Sub

In the above code there is a condition as below If Target.Column = 3 Then

Instead of hard coding the value with 3 i would like to apply this logic for the complete column which contains the value ACTION in one of its cell in that column.

Answer 1

Use a Find to determine the (first) column containing Action

Sub GetAction()
Dim rng1 As Range
Set rng1 = ActiveSheet.UsedRange.Find("Action", , xlValues, xlWhole)
If Not rng1 Is Nothing Then
MsgBox "Found in column " & rng1.Column
Else
MsgBox "Not found", vbCritical
End If
End Sub