This should be very simple, but my efforts with unlist
or matrix
failed.
How can you export the following list into an excel sheet that preserves the same structure?
list(structure(list(rob = c(0.500395231401348, 0.839314035292317,
0.710466394967634, 0.61574235723249)), .Names = "rob", row.names = c(NA,
4L), class = "data.frame"), structure(list(rob = c(0.66163340478379,
0.591092739290417, 0.554484883310407, 0.78199375944331, 0.489388775242085
)), .Names = "rob", row.names = c(NA, 5L), class = "data.frame"),
structure(list(rob = c(0.697897964659196, 0.480394119894312,
0.514294379103359, 0.626971885076273, 0.77938643423231, 0.618135503224601
)), .Names = "rob", row.names = c(NA, 6L), class = "data.frame"))
Thanks!
You can do it by:
NA
to make all vectors the same lengthdo.call(rbind, ...)
to create a data frameLike this:
xx <- lapply(x, unlist)
max <- max(sapply(xx, length))
do.call(rbind, lapply(xx, function(z)c(z, rep(NA, max-length(z)))))
rob1 rob2 rob3 rob4
[1,] 0.5003952 0.8393140 0.7104664 0.6157424 NA NA
[2,] 0.6616334 0.5910927 0.5544849 0.7819938 0.4893888 NA
[3,] 0.6978980 0.4803941 0.5142944 0.6269719 0.7793864 0.6181355
Then it's a simple mattter of using write.table()
or your favourite export to excel method.
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