Getting all attributes to appear on python's `__dict__` method

Question

Please consider the following python example:

In [3]: class test(object):
   ...:     attribute='3'
   ...:     def __init__(self):
   ...:         self.other='4'
   ...:         

In [4]: b=test()

In [5]: b.attribute
Out[5]: '3'

In [6]: b.__dict__
Out[6]: {'other': '4'}

Why is it that __dict__ only shows the "other" attribute and not "atribute"?

And how do I get a dictionary with all the classe's attributes and values? That is, how do I get this?

{'other': '4', 'attribute': '3'}

And I mean by using __dict__ or by some other simple means.

PS: related to this question, but couldn't quite get a dict from there.

PS2: I'm not look for test.__dict__ or b.__class__.__dict__, I'm looking for something that can be used as

In [3]: class test(object):
   ...:     attribute='3'
   ...:     def __init__(self):
   ...:         self.other='4'
   ...:     def _print_atr(self):
   ...:         # This should print exactly {'other': '4', 'attribute': '3'}
   ...:         print(self.__all_atr__)

In [4]: b=test()

In [5]: b.attribute
Out[5]: '3'

In [6]: b.__dict__
Out[6]: {'other': '4'}

Cheers

Answer 1

attribute is not an instance attribute but a class attribute (can be seen in the mappingproxy test.__dict__).

You can get attribute in the instance __dict__ if you update the value of attribute from the instance:

>>> b = test()
>>> b.__dict__
{'other': '4'}
>>> b.attribute
'3'
>>> b.attribute = 5
>>> b.__dict__
{'attribute': 5, 'other': '4'}

Or keep the original value with

>>> b.attribute  = b.__class__.attribute # may not be necessary

Or you could change the definition of the class and move attribute into one of the class methods and bind it to the instance via self.