Is there a way to get an absolute path to the Perl executable for the current process?
$^X
will give me the Perl executable name, but the doc states that it will sometimes be a relative path, and this seems to be true on OS X for example.
ExtUtils::MakeMaker
seems to have some magic to find the absolute path, since the Makefile it generates on my OS X contains
PERL = /usr/local/bin/perl
FULLPERL = /usr/local/bin/perl
but I have no idea how it does this or whether the magic is readily accessible to others.
EDIT: Thanks Borodin for the $Config{perlpath}
tip. Grepping for this in ExtUtils
, I found this tidbit in ExtUtils::MM_Unix::_fixin_replace_shebang
, which I guess is what MakeMaker uses to replace #!perl
with the correct shebang line.
if ( $Config{startperl} =~ m,^\#!.*/perl, ) {
$interpreter = $Config{startperl};
$interpreter =~ s,^\#!,,;
}
else {
$interpreter = $Config{perlpath};
}
The perl executable is normally installed in /usr/bin or /usr/local/bin on your machine. Some people often refer to perl as the Perl interpreter, but this isn't strictly correct, as you'll learn shortly.
I think what you're looking for is $Config{perlpath}
.
If you want your code to be very portable you may have to append a file type to that value; this is described in the perlport
documentation. Otherwise all you need is this:
use Config;
my $perl = $Config{perlpath};
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