Getopt shift optarg

Question

I need to call my program like this:

./program hello -r foo bar

I take hello out of argv[1], but i am having trouble with value bar, also should i change "r:" to something else?

while((c = getopt(argc, argv, "r:")) != -1){
   switch(i){
   ...
   case 'r':
     var_foo = optarg;
     //shell like argument shift here?
     var_bar = optarg;
     break;
...}

I know I could do this with passing through argv, but is there a way to do it with getopt similar way as in bash?

Thanks.

Answer 1

bar is not an option argument in the eyes of getopt. Rather, GNU getopt rearranges the positional arguments so that at the end of the processing, you have argv[3] being "hello" and argv[4] being "bar". Basically, when you're done getopting, you still have positional arguments [optind, argc) to process:

int main(int argc, char * argv[])
{
     {
         int c;
         while ((c = getopt(argc, argv, ...)) != -1) { /* ... */ }
     }

     for (int i = optind; i != argc; ++i)
     {
         // have positional argument argv[i]
     }
}