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#define offsetof(type, member) ((size_t)(&((type *)0)->member))
I am not understanding (&((type *)0)->member) what is this exactly telling me.....
here type may be a structure or something else??...
More specifically what is that 0 telling me here??
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This is to determine the offset of a struct field. It works by using 0 as the address of the struct, then asking for the address of the field:
(type *)0
is 0 as a pointer to type
&((type *)0)->member
is the address of that hypothetical struct's member member. If the address of the struct is 0, then the address of the member is the same as the offset from the beginning of the struct.
((size_t)(&((type *)0)->member))
is that address cast to a size_t to be the proper type for an offset.
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