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I'm currently using boost::intrusive_ptr together with my GUI classes. Although this is more or less a convenience question, is there a proper way to get the typename of the current class? The reason I'm asking is that I have a macro for typedef'ing the different pointer types:
#define INTRUSIVE_PTR_TYPEDEFS(CLASSNAME) typedef boost::intrusive_ptr<CLASSNAME> Ptr; \
typedef boost::intrusive_ptr<const CLASSNAME> CPtr; \
typedef CLASSNAME* WeakPtr; \
typedef const CLASSNAME* CWeakPtr;
...
class Widget
{
public:
INTRUSIVE_PTR_TYPEDEFS(Widget);
...
};
class Button : public Widget
{
public:
INTRUSIVE_PTR_TYPEDEFS(Button);
...
};
It would be much more comfortable to have CLASSNAME automatically deduced so you could simply copy'n'paste it into the class body. I'm using the compiler shipped with Visual Studio 2010.
Thanks in advance!
499
Similarly, typedef can be used to define a structure, union, or C++ class.
A typedef is scoped exactly as the object declaration would have been, so it can be file scoped or local to a block or (in C++) to a namespace or class.
The typedef keyword allows the programmer to create new names for types such as int or, more commonly in C++, templated types--it literally stands for "type definition". Typedefs can be used both to provide more clarity to your code and to make it easier to make changes to the underlying data types that you use.
No, that's not possible to do in C++.
131
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