How can I get the last day (Dec 31) of the current year as a date using PHP?
I tried the following but this doesn't work:
$year = date('Y');
$yearEnd = strtotime($year . '-12-31');
What I need is a date that looks like 2014-12-31 for the current year.
You can just concatenate actual year with required date
$year = date('Y') . '-12-31';
echo $year;
//output 2014-12-31
PHP strtotime()
uses the current date/time as a basis (so it will use this current year), and you need date()
to format:
$yearEnd = date('Y-m-d', strtotime('Dec 31'));
//or
$yearEnd = date('Y-m-d', strtotime('12/31'));
DateTime is perfectly capable of doing this:
$endOfYear = new \DateTime('last day of December this year');
You can even combine it with more modifiers to get the end of next year:
$endOfNextYear = new \DateTime('last day of December this year +1 years');
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With