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I have a Filter that receives the HttpServletRequest and the request is a POST that consists of an xml that I need to read into my filter method. What is the best way to get the posted xml from the HttpServletRequest object.
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HttpServletRequest and Request Body So when we're dealing with the HTTP requests, HttpServletRequest provides us two ways to read the request body - getInputStream and getReader methods. Each of these methods relies on the same InputStream.
There are two methods for reading the data in the body: getReader() returns a BufferedReader that will allow you to read the body of the request. getInputStream() returns a ServletInputStream if you need to read binary data.
ServletRequest provides basic setter and getter methods for requesting a Servlet, but it doesn't specify how to communicate. HttpServletRequest extends the Interface with getters for HTTP-communication (which is of course the most common way for communicating since Servlets mostly generate HTML).
A ServletRequest object provides data including parameter name and values, attributes, and an input stream. Interfaces that extend ServletRequest can provide additional protocol-specific data (for example, HTTP data is provided by HttpServletRequest .
That depends on how the client has sent it.
If it's been sent as the raw request body, then use ServletRequest#getInputStream():
InputStream xml = request.getInputStream();
// ...
If it's been sent as a regular application/x-www-form-urlencoded request parameter, then use ServletRequest#getParameter():
String xml = request.getParameter("somename");
// ...
If it's been sent as an uploaded file in flavor of a multipart/form-data part, then use HttpServletRequest#getPart().
InputStream xml = request.getPart("somename").getInputStream();
// ...
That were the ways supported by the standard servlet API. Other ways may require a different or 3rd party API (e.g. SOAP).
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