Menu
I have a shell script here:
/node_modules/.bin/exec.sh
in the exec.sh script, I want to obtain the path of the directory's parent directory that the script is contained in (not pwd/cwd!). I can obtain the containing directory like so:
`dirname $0`
which will yield:
/node_modules/.bin
but I am looking to get at one directory higher, I just want to get
/node_modules
I am having trouble searching for the answer, my guess is:
`dirname $1`
but just a guess, not sure if that's right at all. Can anyone give an explanation of how to do this and how it works?
495
You can go back to the parent directory of any current directory by using the command cd .. , as the full path of the current working directory is understood by Bash . You can also go back to your home directory (e.g. /users/jpalomino ) at any time using the command cd ~ (the character known as the tilde).
You can use $BASH_SOURCE : #!/usr/bin/env bash scriptdir="$( dirname -- "$BASH_SOURCE"; )"; Note that you need to use #!/bin/bash and not #!/bin/sh since it's a Bash extension.
I believe the answer is
$(dirname $(dirname "$0"))
don't forget about the double-quotes around "$0"
102
Run dirname twice (nested).
~$ dirname $PWD
/home
~$ dirname `dirname $PWD`
/
~$
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
