Get name of current script in Python

Question

I'm trying to get the name of the Python script that is currently running.

I have a script called foo.py and I'd like to do something like this in order to get the script name:

print(Scriptname) 

Answer 1

You can use __file__ to get the name of the current file. When used in the main module, this is the name of the script that was originally invoked.

If you want to omit the directory part (which might be present), you can use os.path.basename(__file__).

Answer 2

import sys print(sys.argv[0]) 

This will print foo.py for python foo.py, dir/foo.py for python dir/foo.py, etc. It's the first argument to python. (Note that after py2exe it would be foo.exe.)