Get Month & Day from Date

Question

I am trying to get Month and Date from Date in Linux. this is my code

# Set Date 
D="2013/01/17"

# get day 
DD=$(D+"%d")

# get day 
MM=$(D+"%M")

# Day 
echo "Day:"$DD
echo "Month:"$MM

Answer 1

In sh or bash:

D="2013/01/17" DAY=$(date -d "$D" '+%d') MONTH=$(date -d "$D" '+%m') YEAR=$(date -d "$D" '+%Y')  echo "Day: $DAY" echo "Month: $MONTH" echo "Year: $YEAR" 

Answer 2

Or if you want the current date, use date +%Y/%m/%d. If you want them separately you can do something like this:

read YYYY MM DD <<<$(date +'%Y %m %d') echo "Today is Day:$DD Month:$MM" 

An easier approach is:

DD=$(date +%d) MM=$(date +%m) echo "Today is Day:$DD Month:$MM" 

However in this case you're executing date twice, which is inefficient, and if you're really unlucky, the date could change between those two lines ;)

Answer 3

kent$  D="2013/01/17"

kent$  awk -F/ '{print "year:"$1,"Month:"$2,"Day:"$3}'<<<$D
year:2013 Month:01 Day:17

if you want just Month or Day, just leave $2 or $3 there, delete the parts you don't need

Edit

kent$  year=$(awk -F/ '{print $1}' <<<$D)                                                                                                                                   

kent$  echo $year
2013