Get length of a video using regex and ffmpeg

Question

From the following ffmpeg -i output, how would I get the length (00:35)--

$ ffmpeg -i 1video.mp4

Input #0, mov,mp4,m4a,3gp,3g2,mj2, from '/Users/david/Desktop/1video.mp4':
  Metadata:
    major_brand     : isom
    minor_version   : 1
    compatible_brands: isomavc1
     creation_time   : 2010-01-24 00:55:16
  Duration: 00:00:35.08, start: 0.000000, bitrate: 354 kb/s
    Stream #0.0(und): Video: h264 (High), yuv420p, 640x360 [PAR 1:1 DAR 16:9], 597 kb/s, 25 fps, 25 tbr, 25k tbn, 50 tbc
    Metadata:
      creation_time   : 2010-01-24 00:55:16
    Stream #0.1(und): Audio: aac, 44100 Hz, stereo, s16, 109 kb/s
    Metadata:
      creation_time   : 2010-01-24 00:55:17
At least one output file must be specified

Answer 1

This way you get the duration in seconds. I think this is more convenient.

ffprobe -loglevel error -show_streams inputFile.mp3 | grep duration | cut -f2 -d=

ffprobe comes with ffmpeg so you should have it.

EDIT: For a more dedicated version you could use for example

ffprobe -loglevel error -show_format -show_streams inputFile.extension -print_format json

Instead of JSON you could also use e.g. CSV or XML. For more output options look here http://ffmpeg.org/ffprobe.html#Writers