Regex to match whole words that begin with $

Question

I need a regex to match whole words that begin with $. What is the expression, and how can it be tested?

Example:

This $word and $this should be extracted.

In the above sentence, $word and $this would be found.

Answer 1

If you want to match only whole words, you need the word character selector

\B\$\w+

This will match a $ followed by one or more letters, numbers or underscore. Try it out on Rubular

Answer 2

\$(\w+) 

Explanation :

\$ : escape the special $ character
() : capture matches in here (in most engines at least)
\w : match a - z, A - Z and 0 - 9 (and_)
+ : match it any number of times

Answer 3

I think you want something like this:

/(^\$|(?<=\s)\$\w+)/

The first parentheses just captures your result.

^\$ matches the beginning of your entire string followed by a dollar sign;

| gives you a choice OR;

(?<=\s)\$ is a positive look behind that checks if there's a dollar sign \$ with a space \s behind it.

Finally, (to recap) if we have a string that begins with a $ or a $ is preceded by a space, then the regex checks to see if one or more word characters follow - \w+.

This would match:

$test one two three

and

one two three $test one two three

but not

one two three$test