{
"204": {
"host": "https:\/\/abc.com\/production-source\/ChangSha\/2013\/12\/02\/0\/0\/A\/Content\/",
"timestamp": 1385909880,
"cover": ["17\/Pg017.png",
"18\/Pg018.png",
"1\/Pg001.png",
"2\/Pg002.png"],
"year": "2013",
"month": "12",
"day": "02",
"issue": "2013-12-02",
"id": "204"
},
"203": {
"host": "https:\/\/abc.com\/production-source\/ChangSha\/2013\/12\/01\/0\/0\/A\/Content\/",
"timestamp": 1385806902,
"cover": ["1\/Pg001.png",
"2\/Pg002.png",
"3\/Pg003.png",
"4\/Pg004.png"],
"year": "2013",
"month": "12",
"day": "01",
"issue": "2013-12-01",
"id": "203"
},
"202": {
"host": "https:\/\/abc.com\/production-source\/ChangSha\/2013\/11\/30\/0\/0\/A\/Content\/",
"timestamp": 1385720451,
"cover": ["1\/Pg001.png",
"2\/Pg002.png",
"3\/Pg003.png",
"4\/Pg004.png"],
"year": "2013",
"month": "11",
"day": "30",
"issue": "2013-11-30",
"id": "202"
}
}
The above sample json array , how to get the 204, 203 and 202? Thanks
I tried:
JSONArray issueArray = new JSONArray(jsonContent);
for (int j = 0; j < issueArray.length(); j++) {
JSONObject issue = issueArray.getJSONObject(j);
String _pubKey = issue.getString(0);
}
above sample json array , how to get the 204, 203 and 202?
No, current String is JSONObject
instead of JSONArray
. you should get Iterator using JSONObject. keys () if inner JSONObject keys dynamic as:
JSONObject issueObj = new JSONObject(jsonContent);
Iterator iterator = issueObj.keys();
while(iterator.hasNext()){
String key = (String)iterator.next();
JSONObject issue = issueObj.getJSONObject(key);
// get id from issue
String _pubKey = issue.optString("id");
}
Answer given by Mr. K is also right but you can also use jsonObject names() method. please find the sample code
for(int i = 0; i<jsonobject.length(); i++){
Log.e(TAG, "Key = " + jsonobject.names().getString(i) + " value = " + jsonobject.get(jsonobject.names().getString(i)));
}
I hope dis will help you
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