I have the following path:
http://192.168.56.10:4567/browse/foo/bar?x=100&y=200
I want absolutely everything that comes after "http://192.168.56.10:4567/browse/" in a string.
Using a splat doesn't work (only catches "foo/bar"):
get '/browse/*' do
Neither does the regular expression (also only catches "foo/bar"):
get %r{/browse/(.*)} do
The x and y params are all accessible in the params hash, but doing a .map on the ones I want seems unreasonable and un-ruby-like (also, this is just an example.. my params are actually very dynamic and numerous). Is there a better way to do this?
More info: my path looks this way because it is communicating with an API and I use the route to determine the API call I will make. I need the string to look this way.
If you are willing to ignore hash tag in path param this should work(BTW browser would ignore anything after hash in URL)
updated answer
get "/browse/*" do
p "#{request.path}?#{request.query_string}".split("browse/")[1]
end
Or even simpler
request.fullpath.split("browse/")[1]
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