Get escaped URL parameter

Question

I'm looking for a jQuery plugin that can get URL parameters, and support this search string without outputting the JavaScript error: "malformed URI sequence". If there isn't a jQuery plugin that supports this, I need to know how to modify it to support this.

?search=%E6%F8%E5 

The value of the URL parameter, when decoded, should be:

æøå 

(the characters are Norwegian).

I don't have access to the server, so I can't modify anything on it.

Answer 1

function getURLParameter(name) {     return decodeURI(         (RegExp(name + '=' + '(.+?)(&|$)').exec(location.search)||[,null])[1]     ); } 

Answer 2

Below is what I have created from the comments here, as well as fixing bugs not mentioned (such as actually returning null, and not 'null'):

function getURLParameter(name) {     return decodeURIComponent((new RegExp('[?|&]' + name + '=' + '([^&;]+?)(&|#|;|$)').exec(location.search)||[,""])[1].replace(/\+/g, '%20'))||null; }