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Get current number of partitions of a DataFrame

Is there any way to get the current number of partitions of a DataFrame? I checked the DataFrame javadoc (spark 1.6) and didn't found a method for that, or am I just missed it? (In case of JavaRDD there's a getNumPartitions() method.)

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kecso Avatar asked Feb 11 '17 02:02

kecso


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Is there any way to get the current number of partitions of a DataFrame?

Similarly, in PySpark you can get the current length/size of partitions by running getNumPartitions() of RDD class, so to use with DataFrame first you need to convert to RDD.

How do I print the number of partitions in a DataFrame PySpark?

➠ getNumPartitions: RDD function getNumPartitions can be used to get the number of partition in a dataframe. Example 1: Dataframe "df" was converted to RDD using rdd attribute and then getNumPartitions function was applied on it to get number of partitions.

How do I know how many partitions I have?

The number of partitions of n is given by the partition function p(n). So p(4) = 5. The notation λ ⊢ n means that λ is a partition of n. Partitions can be graphically visualized with Young diagrams or Ferrers diagrams.


2 Answers

You need to call getNumPartitions() on the DataFrame's underlying RDD, e.g., df.rdd.getNumPartitions(). In the case of Scala, this is a parameterless method: df.rdd.getNumPartitions.

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user4601931 Avatar answered Nov 03 '22 08:11

user4601931


dataframe.rdd.partitions.size is another alternative apart from df.rdd.getNumPartitions() or df.rdd.length.

let me explain you this with full example...

val x = (1 to 10).toList val numberDF = x.toDF(“number”) numberDF.rdd.partitions.size // => 4 

To prove that how many number of partitions we got with above... save that dataframe as csv

numberDF.write.csv(“/Users/Ram.Ghadiyaram/output/numbers”) 

Here is how the data is separated on the different partitions.

Partition 00000: 1, 2 Partition 00001: 3, 4, 5 Partition 00002: 6, 7 Partition 00003: 8, 9, 10 

Update :

@Hemanth asked a good question in the comment... basically why number of partitions are 4 in above case

Short answer : Depends on cases where you are executing. since local[4] I used, I got 4 partitions.

Long answer :

I was running above program in my local machine and used master as local[4] based on that it was taking as 4 partitions.

val spark = SparkSession.builder()     .appName(this.getClass.getName)     .config("spark.master", "local[4]").getOrCreate() 

If its spark-shell in master yarn I got the number of partitions as 2

example : spark-shell --master yarn and typed same commands again

scala> val x = (1 to 10).toList x: List[Int] = List(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)   scala> val numberDF = x.toDF("number") numberDF: org.apache.spark.sql.DataFrame = [number: int]  scala> numberDF.rdd.partitions.size res0: Int = 2 
  • here 2 is default parllelism of spark
  • Based on hashpartitioner spark will decide how many number of partitions to distribute. if you are running in --master local and based on your Runtime.getRuntime.availableProcessors() i.e. local[Runtime.getRuntime.availableProcessors()] it will try to allocate those number of partitions. if your available number of processors are 12 (i.e. local[Runtime.getRuntime.availableProcessors()]) and you have list of 1 to 10 then only 10 partitions will be created.

NOTE:

If you are on a 12-core laptop where I am executing spark program and by default the number of partitions/tasks is the number of all available cores i.e. 12. that means local[*] or s"local[${Runtime.getRuntime.availableProcessors()}]") but in this case only 10 numbers are there so it will limit to 10

keeping all these pointers in mind I would suggest you to try on your own

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Ram Ghadiyaram Avatar answered Nov 03 '22 09:11

Ram Ghadiyaram