get file list of files contained in a zip file

Question

What you need is ZipFile.namelist() that will give you a list of all the contents of the archive, you can then do a zip.open('filename_you_discover') to get the contents of that file.

import zipfile

# zip file handler  
zip = zipfile.ZipFile('filename.zip')

# list available files in the container
print (zip.namelist())

# extract a specific file from the zip container
f = zip.open("file_inside_zip.txt")

# save the extraced file 
content = f.read()
f = open('file_inside_zip.extracted.txt', 'wb')
f.write(content)
f.close()

import zipfile

zip=zipfile.ZipFile('my_zip.zip')
f=zip.open('my_txt_file.txt')
contents=f.read()
f.close()

You can see the documentation here. In particular, the namelist() method will give you the names of the zip file members.