If I try to parse a broken XML the exception shows the line number. Is there a way to show the XML context?
I want to see the xml tags before and after the broken part.
Example:
import xml.etree.ElementTree as ET
tree = ET.fromstring('<a><b></a>')
Exception:
Traceback (most recent call last):
File "tmp/foo.py", line 2, in <module>
tree = ET.fromstring('<a><b></a>')
File "/usr/lib/python2.7/xml/etree/ElementTree.py", line 1300, in XML
parser.feed(text)
File "/usr/lib/python2.7/xml/etree/ElementTree.py", line 1642, in feed
self._raiseerror(v)
File "/usr/lib/python2.7/xml/etree/ElementTree.py", line 1506, in _raiseerror
raise err
xml.etree.ElementTree.ParseError: mismatched tag: line 1, column 8
Something like this would be nice:
ParseError:
<a><b></a>
=====^
You could make a helper function to do this:
import sys
import io
import itertools as IT
import xml.etree.ElementTree as ET
PY2 = sys.version_info[0] == 2
StringIO = io.BytesIO if PY2 else io.StringIO
def myfromstring(content):
try:
tree = ET.fromstring(content)
except ET.ParseError as err:
lineno, column = err.position
line = next(IT.islice(StringIO(content), lineno))
caret = '{:=>{}}'.format('^', column)
err.msg = '{}\n{}\n{}'.format(err, line, caret)
raise
return tree
myfromstring('<a><b></a>')
yields
xml.etree.ElementTree.ParseError: mismatched tag: line 1, column 8
<a><b></a>
=======^
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