Get an attribute value based on the name attribute with BeautifulSoup

Question

I want to print an attribute value based on its name, take for example

<META NAME="City" content="Austin"> 

I want to do something like this

soup = BeautifulSoup(f)  # f is some HTML containing the above meta tag for meta_tag in soup("meta"):     if meta_tag["name"] == "City":         print(meta_tag["content"]) 

The above code give a KeyError: 'name', I believe this is because name is used by BeatifulSoup so it can't be used as a keyword argument.

Answer 1

It's pretty simple, use the following -

>>> from bs4 import BeautifulSoup >>> soup = BeautifulSoup('<META NAME="City" content="Austin">') >>> soup.find("meta", {"name":"City"}) <meta name="City" content="Austin" /> >>> soup.find("meta", {"name":"City"})['content'] u'Austin' 

Leave a comment if anything is not clear.

Answer 2

theharshest answered the question but here is another way to do the same thing. Also, In your example you have NAME in caps and in your code you have name in lowercase.

s = '<div class="question" id="get attrs" name="python" x="something">Hello World</div>' soup = BeautifulSoup(s)  attributes_dictionary = soup.find('div').attrs print attributes_dictionary # prints: {'id': 'get attrs', 'x': 'something', 'class': ['question'], 'name': 'python'}  print attributes_dictionary['class'][0] # prints: question  print soup.find('div').get_text() # prints: Hello World