I want to list out all the case classes which implements a particular trait. I am currently using Clapper ClassUtil for doing that. I am able to get the case classes that are directly implementing a trait. However, I am not able to get the other classes which are not directly implementing the trait. How can I get all classes which directly or indirectly implements a trait. ?
val finder = ClassFinder()
finder.getClasses().filter(_.isConcrete).filter(_.implements("com.myapp.MyTrait"))
Scala Version : 2.11
Clapper Class Util Version : 1.0.6
Is there any other way I can get these information? Can someone point me to the right direction?
I tried using scala.reflect
but could not understand how to get the info.
EDIT:
Sample traits and usages:
trait BaseEntity
trait NamedEntity{ val name:String}
trait MasterDataEntity extends NamedEntity
case class Department(id:Long, override val name:String) extends MasterDataEntity
case class Employee(id:Long, name:String) extends BaseEntity
case class User(id:Long, override val name:String) extends NamedEntity
Now, if I give the trait as NamedEntity
, I should be able to get both Department
and User
since they both are directly or indirectly implementing NamedEntity. With implements
method, it will give only User. I also tried by using interfaces
method, which will also provide the direct super classes only.
In Scala, we are allowed to implement the method(only abstract methods) in traits. If a trait contains method implementation, then the class which extends this trait need not implement the method which already implemented in a trait. As shown in the below example. Traits does not contain constructor parameters.
Scala reflection enables a form of metaprogramming which makes it possible for programs to modify themselves at compile time. This compile-time reflection is realized in the form of macros, which provide the ability to execute methods that manipulate abstract syntax trees at compile-time.
Unlike a class, Scala traits cannot be instantiated and have no arguments or parameters. However, you can inherit (extend) them using classes and objects.
In scala, trait is a collection of abstract and non-abstract methods. You can create trait that can have all abstract methods or some abstract and some non-abstract methods. A variable that is declared either by using val or var keyword in a trait get internally implemented in the class that implements the trait.
Looking at the source code, the problem seems to be that it doesn't follow the interfaces hierarchy. If you do that, you find all instances:
package foo
import java.io.File
import org.clapper.classutil.{ClassFinder, ClassInfo}
object Main extends App {
val jar = new File("target/scala-2.11/class_test_2.11-0.1.0.jar")
val finder = ClassFinder(jar :: Nil)
val classes = ClassFinder.classInfoMap(finder.getClasses().iterator)
val impl = find("foo.NamedEntity", classes)
impl.foreach(println)
def find(ancestor: String, classes: Map[String, ClassInfo]): List[ClassInfo] =
classes.get(ancestor).fold(List.empty[ClassInfo]) { ancestorInfo =>
val ancestorName = ancestorInfo.name
def compare(info: ClassInfo): Boolean =
info.name == ancestorName ||
(info.superClassName :: info.interfaces).exists {
n => classes.get(n).exists(compare)
}
val it = classes.valuesIterator
it.filter { info => info.isConcrete && compare(info) } .toList
}
}
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