TMyBaseClass=class
constructor(test:integer);
end;
TMyClass=class(TMyBaseClass);
TClass1<T: TMyBaseClass,constructor>=class()
public
FItem: T;
procedure Test;
end;
procedure TClass1<T>.Test;
begin
FItem:= T.Create;
end;
var u: TClass1<TMyClass>;
begin
u:=TClass1<TMyClass>.Create();
u.Test;
end;
How do I make it to create the class with the integer param. What is the workaround?
Just typecast to the correct class:
type
TMyBaseClassClass = class of TMyBaseClass;
procedure TClass1<T>.Test;
begin
FItem:= T(TMyBaseClassClass(T).Create(42));
end;
Also it's probably a good idea to make the constructor virtual.
You might consider giving the base class an explicit method for initialization instead of using the constructor:
TMyBaseClass = class
public
procedure Initialize(test : Integer); virtual;
end;
TMyClass = class(TMyBaseClass)
public
procedure Initialize(test : Integer); override;
end;
procedure TClass1<T>.Test;
begin
FItem:= T.Create;
T.Initialize(42);
end;
Of course this only works, if the base class and all subclasses are under your control.
Update
The solution offered by @TOndrej is far superior to what I wrote below, apart from one situation. If you need to take runtime decisions as to what class to create, then the approach below appears to be the optimal solution.
I've refreshed my memory of my own code base which also deals with this exact problem. My conclusion is that what you are attempting to achieve is impossible. I'd be delighted to be proved wrong if anyone wants to rise to the challenge.
My workaround is for the generic class to contain a field FClass
which is of type class of TMyBaseClass
. Then I can call my virtual constructor with FClass.Create(...)
. I test that FClass.InheritsFrom(T)
in an assertion. It's all depressingly non-generic. As I said, if anyone can prove my belief wrong I will upvote, delete, and rejoice!
In your setting the workaround might look like this:
TMyBaseClass = class
public
constructor Create(test:integer); virtual;
end;
TMyBaseClassClass = class of TMyBaseClass;
TMyClass = class(TMyBaseClass)
public
constructor Create(test:integer); override;
end;
TClass1<T: TMyBaseClass> = class
private
FMemberClass: TMyBaseClassClass;
FItem: T;
public
constructor Create(MemberClass: TMyBaseClassClass); overload;
constructor Create; overload;
procedure Test;
end;
constructor TClass1<T>.Create(MemberClass: TMyBaseClassClass);
begin
inherited Create;
FMemberClass := MemberClass;
Assert(FMemberClass.InheritsFrom(T));
end;
constructor TClass1<T>.Create;
begin
Create(TMyBaseClassClass(T));
end;
procedure TClass1<T>.Test;
begin
FItem:= T(FMemberClass.Create(666));
end;
var
u: TClass1<TMyClass>;
begin
u:=TClass1<TMyClass>.Create(TMyClass);
u.Test;
end;
Another more elegant solution, if it is possible, is to use a parameterless constructor and pass in the extra information in a virtual method of T
, perhaps called Initialize
.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With