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I only know how I can generate a random boolean value (true/false). The default probability is 50:50
But how can I generate a true false value with my own probability? Let's say it returns true with a probability of 40:60 or 20:80 etc...
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In order to generate Random boolean in Java, we use the nextBoolean() method of the java. util. Random class. This returns the next random boolean value from the random generator sequence.
Until now I used the following code to generate a random bool : bool randomBool() { return 0 + (rand() % (1 - 0 + 1)) == 1; } // In main. cpp time_t seconds; time(&seconds); srand((unsigned int) seconds);
Use the NextDouble() Method From C# Class Random The NextDouble() returns a random double value between 0.0 and 1.0 . So, we can add a separator at any place between these two numbers and divide the numbers generated into true or false based on a separation condition.
Well, one way is Random.Next(100) <= 20 ? true : false, using the integer value of NextInt to force your own probability. I can't speak to the true 'randomness' of this method though.
More detailed example:
Random gen = new Random(); int prob = gen.Next(100); return prob <= 20; If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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