I have a row with numbers 1:n
. I'm looking to add a second row also with the numbers 1:n
but these should be in a random order while satisfying the following:
For example, in the following
Row 1: 1 2 3 4 5 6 7 ...
Row 2: 3 6 15 8 13 12 7 ...
the number 7 occurs at the same position in both rows 1 and 2 (namely position 7; thereby not satisfying rule 1)
while in the following
Row 1: 1 2 3 4 5 6 7 ...
Row 2: 3 7 15 8 13 12 2 ...
the combination of 2+7 appears twice (in positions 2 and 7; thereby not satisfying rule 2).
It would perhaps be possible – but unnecessarily time-consuming – to do this by hand (at least up until a reasonable number), but there must be quite an elegant solution for this in MATLAB.
This problem is called a derangment of a permutation.
Use the function randperm, in order to find a random permutation of your data.
x = [1 2 3 4 5 6 7];
y = randperm(x);
Then, you can check that the sequence is legal. If not, do it again and again..
You have a probability of about 0.3 each time to succeed, which means that you need roughly 10/3 times to try until you find it.
Therefore you will find the answer really quickly.
Alternatively, you can use this algorithm to create a random derangment.
Edit
If you want to have only cycles of size > 2, this is a generalization of the problem. In it is written that the probability in that case is smaller, but big enough to find it in a fixed amount of steps. So the same approach is still valid.
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