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Reversing a regular expression in python
I think I ran into a problem that sounds easier than it is... I'm not too sure. I want to define a regular expression, and I want to build a number of strings matching it.
Is there any module I can import that has got this functionality? Preferably not a brute-force approach using re.search or re.match. There must be a more elegant way to do that.
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Just enter your regexp in the field below, press the Generate Text button, and you'll get a random text that matches your regexp. Press a button – invert a regexp. No ads, nonsense, or garbage.
If you want to split a string that matches a regular expression (regex) instead of perfect match, use the split() of the re module. In re. split() , specify the regex pattern in the first parameter and the target character string in the second parameter. An example of split by consecutive numbers is as follows.
Both return the first match of a substring found in the string, but re. match() searches only from the beginning of the string and return match object if found. But if a match of substring is found somewhere in the middle of the string, it returns none.
I've been working on a little helper library for generating random strings with Python
It includes a method, xeger() that allows you to create a string from a regex:
>>> import rstr >>> rstr.xeger(r'[A-Z]\d[A-Z] \d[A-Z]\d') u'M5R 2W4' Right now, it works with most basic regular expressions.
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The exrex module does this: https://github.com/asciimoo/exrex.
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For some regular expressions, the list of possible strings can be infinite. For example:
a*
includes
a
aa
aaa
etc. Thus, there is no way to generate all strings for a given regex.
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