Generate a class from an Interface

Question

Suppose I have a new interface:

public interface IClientRepository 
{
    void Add(Customer customer);
    void Remove(Customer customer);
    Customer Get(long id);
}

Now I'd like to do the following:

• Create a new class with a good default name (e.g. "ClientRepository");
• Have that class in a file as a sibling of the interface code file.

I think I've seen instructors of Pluralsight videos do this on numerous occasions, but I can't seem to find out what keyboard shortcuts to use for this.

What have I tried? Well:

• Google Fu mostly provides a way to do the opposite (extract interface), e.g. posts like this.
• Read through the Refactorings docs for ReSharper as well as those for Code Generation.
• Hit CTRL + SHIFT + r on the interface declaration, but none of the options seems to be what I need.

What am I missing here? How do you generate a class from an interface?

Answer 1

1. Put the cursor on the interface type name, for instance here:

    public interface |IClientRepository 
   

   Hit Alt+Enter, and select Create Derived Type. This creates a class called ClientRepository in the same file as IClientRepository.

2. Now put your cursor on the class type name of ClientRepository, and hit Ctrl+R, Ctrl+O and select Move to another file. It will default to a file name that matches the type name and puts it in the same directory as the file it was moved from.