I have a table Persons with personaldata and so on. There are lots of columns but the once of interest here are: addressindex
, lastname
and firstname
where addressindex
is a unique address drilled down to the door of the apartment. So if I have 'like below' two persons with the lastname
and one the firstnames
are the same they are most likely duplicates.
I need a way to list these duplicates.
tabledata: personid 1 firstname "Carl" lastname "Anderson" addressindex 1 personid 2 firstname "Carl Peter" lastname "Anderson" addressindex 1
I know how do this if I were to match exactly on all columns but I need fuzzy match to do the trick with (from the above example) a result like:
Row personid addressindex lastname firstname 1 2 1 Anderson Carl Peter 2 1 1 Anderson Carl .....
Any hints on how to solve this in a good way?
A technique of finding the strings that match a pattern approximately (rather than exactly). Users / Reviewers often capture names inaccurately.
Fuzzy Matching (also called Approximate String Matching) is a technique that helps identify two elements of text, strings, or entries that are approximately similar but are not exactly the same. For example, let's take the case of hotels listing in New York as shown by Expedia and Priceline in the graphic below.
Specifies a search condition for a graph. MATCH can be used only with graph node and edge tables, in the SELECT statement as part of WHERE clause.
Fuzzy matching (FM), also known as fuzzy logic, approximate string matching, fuzzy name matching, or fuzzy string matching is an artificial intelligence and machine learning technology that identifies similar, but not identical elements in data table sets.
I've found that the stuff SQL Server gives you to do fuzzy matching is pretty clunky. I've had really good luck with my own CLR functions using the Levenshtein distance algorithm and some weighting. Using that algorithm, I've then made a UDF called GetSimilarityScore that takes two strings and returns a score between 0.0 and 1.0. The closer to 1.0 the match is, the better. Then, query with a threshold of >=0.8 or so to get the most likely matches. Something like this:
if object_id('tempdb..#similar') is not null drop table #similar select a.id, ( select top 1 x.id from MyTable x where x.id <> a.id order by dbo.GetSimilarityScore(a.MyField, x.MyField) desc ) as MostSimilarId into #similar from MyTable a select *, dbo.GetSimilarityScore(a.MyField, c.MyField) from MyTable a join #similar b on a.id = b.id join MyTable c on b.MostSimilarId = c.id
Just don't do it with really large tables. It's a slow process.
Here's the CLR UDFs:
''' <summary> ''' Compute the distance between two strings. ''' </summary> ''' <param name="s1">The first of the two strings.</param> ''' <param name="s2">The second of the two strings.</param> ''' <returns>The Levenshtein cost.</returns> <Microsoft.SqlServer.Server.SqlFunction()> _ Public Shared Function ComputeLevenstheinDistance(ByVal string1 As SqlString, ByVal string2 As SqlString) As SqlInt32 If string1.IsNull OrElse string2.IsNull Then Return SqlInt32.Null Dim s1 As String = string1.Value Dim s2 As String = string2.Value Dim n As Integer = s1.Length Dim m As Integer = s2.Length Dim d As Integer(,) = New Integer(n, m) {} ' Step 1 If n = 0 Then Return m If m = 0 Then Return n ' Step 2 For i As Integer = 0 To n d(i, 0) = i Next For j As Integer = 0 To m d(0, j) = j Next ' Step 3 For i As Integer = 1 To n 'Step 4 For j As Integer = 1 To m ' Step 5 Dim cost As Integer = If((s2(j - 1) = s1(i - 1)), 0, 1) ' Step 6 d(i, j) = Math.Min(Math.Min(d(i - 1, j) + 1, d(i, j - 1) + 1), d(i - 1, j - 1) + cost) Next Next ' Step 7 Return d(n, m) End Function ''' <summary> ''' Returns a score between 0.0-1.0 indicating how closely two strings match. 1.0 is a 100% ''' T-SQL equality match, and the score goes down from there towards 0.0 for less similar strings. ''' </summary> <Microsoft.SqlServer.Server.SqlFunction()> _ Public Shared Function GetSimilarityScore(string1 As SqlString, string2 As SqlString) As SqlDouble If string1.IsNull OrElse string2.IsNull Then Return SqlInt32.Null Dim s1 As String = string1.Value.ToUpper().TrimEnd(" "c) Dim s2 As String = string2.Value.ToUpper().TrimEnd(" "c) If s1 = s2 Then Return 1.0F ' At this point, T-SQL would consider them the same, so I will too Dim flatLevScore As Double = InternalGetSimilarityScore(s1, s2) Dim letterS1 As String = GetLetterSimilarityString(s1) Dim letterS2 As String = GetLetterSimilarityString(s2) Dim letterScore As Double = InternalGetSimilarityScore(letterS1, letterS2) 'Dim wordS1 As String = GetWordSimilarityString(s1) 'Dim wordS2 As String = GetWordSimilarityString(s2) 'Dim wordScore As Double = InternalGetSimilarityScore(wordS1, wordS2) If flatLevScore = 1.0F AndAlso letterScore = 1.0F Then Return 1.0F If flatLevScore = 0.0F AndAlso letterScore = 0.0F Then Return 0.0F ' Return weighted result Return (flatLevScore * 0.2F) + (letterScore * 0.8F) End Function Private Shared Function InternalGetSimilarityScore(s1 As String, s2 As String) As Double Dim dist As SqlInt32 = ComputeLevenstheinDistance(s1, s2) Dim maxLen As Integer = If(s1.Length > s2.Length, s1.Length, s2.Length) If maxLen = 0 Then Return 1.0F Return 1.0F - Convert.ToDouble(dist.Value) / Convert.ToDouble(maxLen) End Function ''' <summary> ''' Sorts all the alpha numeric characters in the string in alphabetical order ''' and removes everything else. ''' </summary> Private Shared Function GetLetterSimilarityString(s1 As String) As String Dim allChars = If(s1, "").ToUpper().ToCharArray() Array.Sort(allChars) Dim result As New StringBuilder() For Each ch As Char In allChars If Char.IsLetterOrDigit(ch) Then result.Append(ch) End If Next Return result.ToString() End Function ''' <summary> ''' Removes all non-alpha numeric characters and then sorts ''' the words in alphabetical order. ''' </summary> Private Shared Function GetWordSimilarityString(s1 As String) As String Dim words As New List(Of String)() Dim curWord As StringBuilder = Nothing For Each ch As Char In If(s1, "").ToUpper() If Char.IsLetterOrDigit(ch) Then If curWord Is Nothing Then curWord = New StringBuilder() End If curWord.Append(ch) Else If curWord IsNot Nothing Then words.Add(curWord.ToString()) curWord = Nothing End If End If Next If curWord IsNot Nothing Then words.Add(curWord.ToString()) End If words.Sort(StringComparer.OrdinalIgnoreCase) Return String.Join(" ", words.ToArray()) End Function
In addition to the other good info here, you might want to consider using the Double Metaphone phonetic algorithm which is generally considered to be better than SOUNDEX.
Tim Pfeiffer details an implementation in SQL in his article Double Metaphone Sounds Great Convert the C++ Double Metaphone algorithm to T-SQL (originally in SQL Mag & then in SQL Server Pro).
That will assist in matching names with slight misspellings, e.g., Carl vs. Karl.
Update: The actual downloadable code seems to be gone, but here's an implementation found on a github repo that appears to have cloned the original code
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