Let me set the scene..
You can open files in a specific mode like this:
#include <fstream>
int main(){
std::fstream myfile;
myfile.open ("filename", std::ios::app);
return 0;
}
that second parameter is an enumerated type-
which is why you will get a compiler error attempting this:
#include <fstream>
int main(){
std::fstream myfile;
myfile.open ("filename", std::ios::lksdjflskdjflksff);
return 0;
}
In this example, the class doesn't have to account for the second parameter being incorrect, and the programmer never has to worry about passing in a nonsensical value.
Question: Is there a way to write functions that must take a particular type AND a particular value?
Let's say I wanted to re-implement a File Handling class similar to the one above.
The difference is I'm making the second parameter a char instead of an enumerated type.
How could I get something like this to work:
#include "MyFileHandler.h"
int main(){
MyFileHandler myfile1;
myfile.open ("filename", 'a'); //GOOD: a stands for append
myfile.open ("filename", 't'); //GOOD: t stands for truncate
myfile.open ("filename", 'x'); //COMPILER ERROR: openmode can not be the value 'x'
return 0;
}
Going beyond this, can I get the compiler to test the validity of argument values through functional means? Example:
void IOnlyAcceptPrimeNumbers(const int & primeNumber);
int function(void);
int main(){
IOnlyAcceptPrimeNumbers(3); //GOOD: 3 is prime
IOnlyAcceptPrimeNumbers(7); //GOOD: 7 is prime
IOnlyAcceptPrimeNumbers(10); //COMPILER ERROR: 10 is not prime
IOnlyAcceptPrimeNumbers(10+1); //GOOD: 11 is prime
IOnlyAcceptPrimeNumbers(1+1+1+1); //COMPILER ERROR: 4 is not prime
IOnlyAcceptPrimeNumbers(function()); //GOOD: can this somehow be done?
return 0;
}
void IOnlyAcceptPrimeNumbers(const int & primeNumber){return;}
int function(void){return 7;}
I believe i've made it clear what I want to do and why I find it important.
Any solutions out there?
If you want compile-time checked values, you could write templates rather than function arguments:
template <char> void foo(std::string const &); // no implementation
template <> void foo<'a'>(std::string const & s) { /* ... */ }
template <> void foo<'b'>(std::string const & s) { /* ... */ }
Usage:
foo<'a'>("hello world"); // OK
foo<'z'>("dlrow olleh"); // Linker error, `foo<'z'>` not defined.
If you want an actual compiler error rather than just a linker error, you could add a static_assert(false)
into the primary template.
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