Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Function to remove spaces from string/char array in C

Tags:

arrays

c

string

The question asked here is very similar to what I am having a problem with. The difference is that I must pass an argument to a function that removes the spaces and returns the resulting string/char array. I got the code working to remove the spaces but for some reason I am left with trailing characters left over from the original array. I even tried strncpy but I was having lots of errors.

Here is what I have so far:

#include <stdio.h>
#include <string.h>
#define STRINGMAX 1000                                                      /*Maximium input size is 1000 characters*/

char* deblank(char* input)                                                  /* deblank accepts a char[] argument and returns a char[] */
{
    char *output=input;
    for (int i = 0, j = 0; i<strlen(input); i++,j++)                        /* Evaluate each character in the input */
    {
        if (input[i]!=' ')                                                  /* If the character is not a space */
            output[j]=input[i];                                             /* Copy that character to the output char[] */
        else
            j--;                                                            /* If it is a space then do not increment the output index (j), the next non-space will be entered at the current index */
    }
    return output;                                                          /* Return output char[]. Should have no spaces*/
}
int main(void) {
    char input[STRINGMAX];
    char terminate[] = "END\n";                                             /* Sentinal value to exit program */

    printf("STRING DE-BLANKER\n");
    printf("Please enter a string up to 1000 characters.\n> ");
    fgets(input, STRINGMAX, stdin);                                         /* Read up to 1000 characters from stdin */

    while (strcmp(input, terminate) != 0)                                   /* Check for que to exit! */
    {
        input[strlen(input) - 1] = '\0';
        printf("You typed: \"%s\"\n",input);                                /* Prints the original input */
        printf("Your new string is: %s\n", deblank(input));                 /* Prints the output from deblank(input) should have no spaces... DE-BLANKED!!! */

        printf("Please enter a string up to 1000 characters.\n> ");
        fgets(input, STRINGMAX, stdin);                                     /* Read up to another 1000 characters from stdin... will continue until 'END' is entered*/
    }
}
like image 274
John R Avatar asked Oct 26 '12 09:10

John R


1 Answers

After removing the white spaces from the input you have not terminated it with nul-terminator (\0) because the new length is less than or equal to the original string.

Just nul-terminate it at the of end your for loop:

char* deblank(char* input)                                         
{
    int i,j;
    char *output=input;
    for (i = 0, j = 0; i<strlen(input); i++,j++)          
    {
        if (input[i]!=' ')                           
            output[j]=input[i];                     
        else
            j--;                                     
    }
    output[j]=0;
    return output;
}
like image 145
P.P Avatar answered Sep 30 '22 16:09

P.P