There are many situations where slicing operations in 2D arrays produce a 1D array as output, example:
a = np.random.random((3,3))
# array([[ 0.4986962 , 0.65777899, 0.16798398],
# [ 0.02767355, 0.49157946, 0.03178513],
# [ 0.60765513, 0.65030948, 0.14786596]])
a[0,:]
# array([ 0.4986962 , 0.65777899, 0.16798398])
There are workarounds like:
a[0:1,:]
# or
a[0,:][np.newaxis,:]
# array([[ 0.4986962 , 0.65777899, 0.16798398]])
Is there any numpy
built in function that transforms an input array to a given number of dimensions? Like:
np.minndim(a, ndim=2)
NumPy Arrays provides the ndim attribute that returns an integer that tells us how many dimensions the array have.
ndim() function return the number of dimensions of an array.
In NumPy the number of dimensions is referred to as rank. The ndim is the same as the number of axes or the length of the output of x.shape. >>> x.
For finding the minimum element use numpy. min(“array name”) function.
There is np.array(array, copy=False, subok=True, ndmin=N)
. np.atleast_1d
, etc. actually use the reshape method, probably to better support some weird subclasses such as matrix.
For most slicing operations in 2-D you could actually use the matrix class, though I would strongly suggest limiting the usage to those few points in code where its features are heavly used.
You can use np.atleast_1d
, np.atleast_2d
and np.atleast_3d
. Unfortunately I don't think there's currently an N-dimensional version.
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