Is it possible to create a function-pointer with a default parameter, something like
TFunctionPointer = function(sName:AnsiString; tOptional: TObject = nil):smallint;
What I want to achieve:
A function pointer, which can accept a function of type
function A(sName:AnsiString)
or
function B(sName:AnsiString, tOptional: TObject)
How can I achieve this?
Default parameter is just a syntactic sugar - actually function call has two parameters.
But you can use function references and anonymous methods to create such function pointers - function adapters.
type
fnA = function(const sName: AnsiString): integer;
fnB = function(const sName: AnsiString; const tOptional: TObject); integer;
fnRef = reference to function(const sName: AnsiString; const tOptional: TObject): integer;
fnBridge = record
Bridge: fnRef;
class operator Implicit(fn: fnA): fnBridge;
class operator Implicit(fn: fnB): fnBridge;
end;
class operator fnBridge.Implicit(fn: fnA): fnBridge;
begin
Result.Bridge :=
function(const sName: AnsiString; const tOptional: TObject): integer
begin
Result := fn(sName);
end;
end;
class operator fnBridge.Implicit(fn: fnB): fnBridge;
begin
Result.Bridge :=
function(const sName: AnsiString; const tOptional: TObject): integer
begin
Result := fn(sName, tOptional);
end;
end;
function A(const sName: AnsiString): integer;
begin Result := Length(sName) end;
function B(const sName: AnsiString; const tOptional: TObject): integer;
begin Result := Length(sName) - Length(tOptional.ClassName) end;
function Consumer (const Param1, Param2: integer; const Action: fnBridge): integer;
begin
Result := Param1 + Param2 * Action.Bridge('ABCDE', Application);
end;
....
ShowMessage( IntToStr( Consumer(10, 20, A) ));
ShowMessage( IntToStr( Consumer(10, 20, B) ));
PS: since Delphi version was not specified it means that answer for ANY Delphi version suits fine. This method should work wit hany version starting with Delphi 2009 and later.
PPS: references to functions with captured variables are implemented internally as TInterfacedObject
descendants. So overall this is just a reduced case of "Strategy pattern" using "higher-order functions"
That is not possible. In order for a function to be of type TFunctionPointer
, it must declare two parameters.
A default parameter is still a parameter. Your TFunctionPointer
is a function with two parameters. When you call it and supply only one parameter, the compiler supplies the default parameter at the call site. So two parameters are still passed to the function.
To expand on this. Consider the following:
procedure Foo(Bar: Integer=666);
begin
end;
When you call the procedure like this:
Foo();
it looks as though the procedure has no parameters. But that is not the case. The compiler translates your code into this:
Foo(666);
The conclusion is that if you want to allow receipt of functions with different numbers of parameters, you'll need to provide an explicit mechanism to receive those different function types. For instance:
procedure DoSomething(const Callback: TProc<string, TObject>); overload;
begin
Callback(str, obj);
end;
procedure DoSomething(const Callback: TProc<string>); overload;
begin
DoSomething(
procedure(arg1: string; arg2: TObject)
begin
Callback(arg1);
end
);
end;
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