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my code is as follow:
done = False def function(): for loop: code if not comply: done = True #let's say that the code enters this if-statement while done == False: function() For some reason when my code enters the if statement, it doesn't exit the while loop after it's done with function().
BUT, if I code it like this:
done = False while done == False: for loop: code if not comply: done = True #let's say that the code enters this if-statement ...it exits the while loop. What's going on here?
I made sure that my code enters the if-statement. I haven't run the debugger yet because my code has a lot of loops (pretty big 2D array) and I gave up on debugging due to it being so tedious. How come "done" isn't being changed when it's in a function?
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Functions can access global variables and modify them. Modifying global variables in a function is considered poor programming practice. It is better to send a variable in as a parameter (or have it be returned in the 'return' statement).
Use of “global†keyword to modify global variable inside a function. If your function has a local variable with same name as global variable and you want to modify the global variable inside function then use 'global' keyword before the variable name at start of function i.e.
In Python, global keyword allows you to modify the variable outside of the current scope. It is used to create a global variable and make changes to the variable in a local context.
If you want to refer to a global variable in a function, you can use the global keyword to declare which variables are global.
Your issue is that functions create their own namespace, which means that done within the function is a different one than done in the second example. Use global done to use the first done instead of creating a new one.
def function(): global done for loop: code if not comply: done = True An explanation of how to use global can be found here
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done=False def function(): global done for loop: code if not comply: done = True you need to use the global keyword to let the interpreter know that you refer to the global variable done, otherwise it's going to create a different one who can only be read in the function.
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