On a 32-bit system, what does ftell return if the current position indicator of a file opened in binary mode is past the 2GB point? In the C99 standard, is this undefined behavior since ftell must return a long int (maximum value being 2**31-1)?
long int is supposed to be AT LEAST 32-bits, but C99 standard does NOT limit it to 32-bit.
C99 standard does provide convenience types like int16_t & int32_t etc that map to correct bit sizes for a target platform.
ftell() and fseek() are limited to 32 bits (including sign bit) on the vast majority of 32-bit architecture systems. So when there is large file support you run into this 2GB issue.
POSIX.1-2001 and SysV functions for fseek and ftell are fseeko and ftello because they use off_t as the parameter for the offset.
you do need to define compile with -D_FILE_OFFSET_BITS=64 or define it somewhere before including stdio.h to ensure that off_t is 64-bits.
Read about this at the cert.org secure coding guide.
C99 says long int must be at least 32-bits it does NOT say that it cannot be bigger
try the following on x86_64 architecture:
#include <stdio.h>
int main(int argc, char *argv[]) {
FILE *fp;
fp = fopen( "test.out", "w");
if ( !fp )
return -1;
fseek(fp, (1L << 34), SEEK_SET);
fprintf(fp, "\nhello world\n");
fclose(fp);
return 0;
}
Notice that 1L is just a long, this will produce a file that's 17GB and sticks a "\nhello world\n" to the end of it. Which you can verify is there by trivially using tail -n1 test.out or explicitly using:
dd if=test.out skip=$((1 << 25))
Note that dd typically uses block size of (1 << 9) so 34 - 9 = 25 will dump out '\nhello world\n'
This worked for me on Windows32/MinGW to play with a 6GB file
#define _FILE_OFFSET_BITS 64
#include<stdio.h>
int main() {
FILE *f = fopen("largefile.zip","rb");
fseeko64(f, 0, SEEK_END);
off64_t size = ftello64(f);
printf("%llu\n", size);
}
gcc readlargefile.c -c -std=C99 -o readlargefile.exe
Every single detail, the macro, the compiler option, matters.
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