I receive an integer that represents a dollar amount in fractional denominations. I would like an algorithm that can add those numbers without parsing and converting them into doubles or decimals.
For example, I receive the integer 50155, which means 50 and 15.5/32 dollars. I then receive 10210 which is 10 and 21/32 dollars. So 50 15.5/32 + 10 21/32 = 61 4.5/32, thus:
50155 + 10210 = 61045
Again, I want to avoid this:
int a = 50155;
int b = a / 1000;
float c = a % 1000;
float d = b;
d += c / 320f;
// d = 50.484375
I would much prefer this:
int a = 50155;
int b = 10210;
int c = MyClass.Add(a.b); // c = 61045
...
public int Add(int a, int b)
{
// ?????
}
Thanks in advance for the help!
Well I don't think you need to use floating point...
public static int Add(int a, int b)
{
int firstWhole = a / 1000;
int secondWhole = b / 1000;
int firstFraction = a % 1000;
int secondFraction = b % 1000;
int totalFraction = firstFraction + secondFraction;
int totalWhole = firstWhole + secondWhole + (totalFraction / 320);
return totalWhole * 1000 + (totalFraction % 320);
}
Alternatively, you might want to create a custom struct that can convert to and from your integer format, and overloads the + operator. That would allow you to write more readable code which didn't accidentally lead to other integers being treated as this slightly odd format.
EDIT: If you're forced to stick with a "single integer" format but get to adjust it somewhat you may want to consider using 512 instead of 1000. That way you can use simple mask and shift:
public static int Add(int a, int b)
{
int firstWhole = a >> 9;
int secondWhole = b >> 9;
int firstFraction = a & 0x1ff
int secondFraction = b & 0x1ff;
int totalFraction = firstFraction + secondFraction;
int totalWhole = firstWhole + secondWhole + (totalFraction / 320);
return (totalWhole << 9) + (totalFraction % 320);
}
There's still the messing around with 320, but it's at least somewhat better.
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