Formatting timedelta objects [duplicate]

Question

I have two datetime objects. I need to calculate the timedelta between them and then show the output in a specific format.

Alpha_TimeObj = datetime.datetime(int(AlphaTime.strftime('%Y')), int(AlphaTime.strftime('%m')), int(AlphaTime.strftime('%d')), int(AlphaTime.strftime('%H')), int(AlphaTime.strftime('%M')), int(AlphaTime.strftime('%S'))) Beta_TimeObj = datetime.datetime(int(BetaTime.strftime('%Y')), int(BetaTime.strftime('%m')), int(BetaTime.strftime('%d')), int(BetaTime.strftime('%H')), int(BetaTime.strftime('%M')), int(BetaTime.strftime('%S'))) Turnaround_TimeObj = Beta_TimeObj  - Alpha_TimeObj 

An example of this Turnaround_TimeObj time delta is "2 days, 22:13:45". I want to format the output, but I am unable to do so.

print Turnaround_TimeObj.strftime('%H hrs %M mins %S secs') 

doesn't work.

I know one way of doing this will be to convert it to seconds and then divmoding to get the required formatting.

As in:

totalSeconds = Turnaround_TimeObj.seconds hours, remainder = divmod(totalSeconds, 3600) minutes, seconds = divmod(remainder, 60) print '%s:%s:%s' % (hours, minutes, seconds) 

But I was wondering if I can do it in a single line using any date time function like strftime.

Actually converting to seconds doesn't work either. If I convert the time delta "1 day, 3:42:54" to seconds using:

totalSeconds = Turnaround_TimeObj.seconds 

The totalSeconds value is shown as 13374 instead of 99774. i.e. it's ignoring the "day" value.

Answer 1

But I was wondering if I can do it in a single line using any date time function like strftime.

As far as I can tell, there isn't a built-in method to timedelta that does that. If you're doing it often, you can create your own function, e.g.

def strfdelta(tdelta, fmt):     d = {"days": tdelta.days}     d["hours"], rem = divmod(tdelta.seconds, 3600)     d["minutes"], d["seconds"] = divmod(rem, 60)     return fmt.format(**d) 

Usage:

>>> print strfdelta(delta_obj, "{days} days {hours}:{minutes}:{seconds}") 1 days 20:18:12 >>> print strfdelta(delta_obj, "{hours} hours and {minutes} to go") 20 hours and 18 to go 

If you want to use a string format closer to the one used by strftime we can employ string.Template:

from string import Template  class DeltaTemplate(Template):     delimiter = "%"  def strfdelta(tdelta, fmt):     d = {"D": tdelta.days}     d["H"], rem = divmod(tdelta.seconds, 3600)     d["M"], d["S"] = divmod(rem, 60)     t = DeltaTemplate(fmt)     return t.substitute(**d) 

Usage:

>>> print strfdelta(delta_obj, "%D days %H:%M:%S") 1 days 20:18:12 >>> print strfdelta(delta_obj, "%H hours and %M to go") 20 hours and 18 to go 

---

The totalSeconds value is shown as 13374 instead of 99774. I.e. it's ignoring the "day" value.

Note in the example above that you can use timedelta.days to get the "day" value.

Alternatively, from Python 2.7 onwards, timedelta has a total_seconds() method which return the total number of seconds contained in the duration.