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How do I go about echoing only the filename of a file if I iterate a directory with a for loop?
for filename in /home/user/* do echo $filename done; will pull the full path with the file name. I just want the file name.
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If you want the ls command output to only contain file/directory names and their respective sizes, then you can do that using the -h option in combination with -l/-s command line option.
The error "FileNotFoundError: [Errno 2] No such file or directory" is telling you that there is no file of that name in the working directory. So, try using the exact, or absolute path. In the above code, all of the information needed to locate the file is contained in the path string - absolute path.
If you want to display only the filename, you can use basename command. find infa/bdm/server/source/path -type f -iname "source_fname_*. txt" Shell command to find the latest file name in the command task!
If you want a native bash solution
for file in /home/user/*; do echo "${file##*/}" done The above uses Parameter Expansion which is native to the shell and does not require a call to an external binary such as basename
However, might I suggest just using find
find /home/user -type f -printf "%f\n" If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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