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I am trying to add done button in number type input for a TextFormField in flutter but I could not able to do that.
TextFormField(
key: Key(keyValue),
initialValue: valueBuilder,
onSaved: (text) {
fieldsController.text = text.trim();
},
inputFormatters: [inputFormatters],
keyboardType: TextInputType.phoneNumber,)
I want create a keyboard like the below. For the input text form field.
787
You only need signed: true to trigger this workaround. @GiulioPretis Characters are shown but not clickable...so, it allows only Numbers & that is what required in this case. you can set decimal to false here if you want to use All characters from Standard Keyboard.
Steps to show numeric input keyboard in FlutterStep 1: Add TextField widget to your dart file. Step 2: Add keyboardType parameter and assign the TextInputType. number. Step 3: Add inputFormatters parameter and assign the [FilteringTextInputFormatter.
You can simply use textInputAction: TextInputAction. none on the TextField.
The TextField widget is required to set keyboardType: TextInputType. number, and inputFormatters: <TextInputFormatter>[FilteringTextInputFormatter. digitsOnly] to accept numbers only as input.
To show the decimal number soft keyboard in Flutter, just add the following option to your TextField widgets: Note: If you use keyboardType: TextInputType.number, the soft keyboard on iOS will not have the dot (.) symbol That’s it. You can continue exploring more about TextField and other stuff in Flutter by taking a look at the following articles:
@bartwaggoner Flutter currently relies on the system keyboard for text entry, and we don't currently support anything like a keyboard plugin written in Flutter. It would be a fairly massive undertaking since we'd have to integrate with all the underlying platform APIs for all OSes we support.
One option would be to use a TextInputType other than number (i.e. the default keyboard) and add validation logic via the onChanged handler and manipulating the controller you pass in. Another possibility would be to implement an input accessory view in Objective-C.
Create a text field as follows: (The text field is in a dialog which is why the onSubmitted does a Navigator.pop) When keyboard appears it has 0-9, '.' an delete but no Done button. There is no way to 'submit' the number entered into the text field.
Change
keyboardType: TextInputType.number
to
keyboardType: TextInputType.numberWithOptions(signed: true, decimal: true)
I've just created a package for add basic actions to the current keyboards .
You can take a look here :
https://pub.dartlang.org/packages/keyboard_actions
Usage :
import 'package:flutter/material.dart';
import 'package:keyboard_actions/keyboard_actions.dart';
//...
FocusNode _nodeText1 = FocusNode();
FocusNode _nodeText2 = FocusNode();
FocusNode _nodeText3 = FocusNode();
FocusNode _nodeText4 = FocusNode();
FocusNode _nodeText5 = FocusNode();
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text("Keyboard Actions Sample"),
),
body: FormKeyboardActions(
keyboardActionsPlatform: KeyboardActionsPlatform.ALL, //optional
keyboardBarColor: Colors.grey[200], //optional
nextFocus: true, //optional
actions: [
KeyboardAction(
focusNode: _nodeText1,
),
KeyboardAction(
focusNode: _nodeText2,
closeWidget: IconButton(
icon: Icon(Icons.close),
onPressed: () {},
),
),
KeyboardAction(
focusNode: _nodeText3,
onTapAction: () {
showDialog(
context: context,
builder: (context) {
return AlertDialog(
content: Text("Custom Action"),
actions: <Widget>[
FlatButton(
child: Text("OK"),
onPressed: () => Navigator.of(context).pop(),
)
],
);
});
},
),
KeyboardAction(
focusNode: _nodeText4,
displayCloseWidget: false,
),
KeyboardAction(
focusNode: _nodeText5,
closeWidget: Padding(
padding: EdgeInsets.all(5.0),
child: Text("CLOSE"),
),
),
],
child: Padding(
padding: const EdgeInsets.all(15.0),
child: SingleChildScrollView(
child: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
TextField(
keyboardType: TextInputType.number,
focusNode: _nodeText1,
decoration: InputDecoration(
hintText: "Input Number",
),
),
TextField(
keyboardType: TextInputType.text,
focusNode: _nodeText2,
decoration: InputDecoration(
hintText: "Input Text with Custom Close Widget",
),
),
TextField(
keyboardType: TextInputType.number,
focusNode: _nodeText3,
decoration: InputDecoration(
hintText: "Input Number with Custom Action",
),
),
TextField(
keyboardType: TextInputType.text,
focusNode: _nodeText4,
decoration: InputDecoration(
hintText: "Input Text without Close Widget",
),
),
TextField(
keyboardType: TextInputType.number,
focusNode: _nodeText5,
decoration: InputDecoration(
hintText: "Input Number with Custom Close Widget",
),
),
],
),
),
),
),
);
}
You don't need a done button just wrap MaterialApp with a GestureDetector
GestureDetector(
behavior: HitTestBehavior.opaque,
onTap: () {
FocusScopeNode currentFocus = FocusScope.of(context);
if (!currentFocus.hasPrimaryFocus &&
currentFocus.focusedChild != null) {
FocusManager.instance.primaryFocus.unfocus();
}
},
child: MaterialApp(
title: "My title",
home:MyHomeScreen(),
),
);
add this to your TextField
TextField(
...
keyboardType: TextInputType.numberWithOptions(signed: true),
inputFormatters: [
FilteringTextInputFormatter.digitsOnly,
],
...
),
This is how to add Done button to your TextFormField when keyboard is opened:
textInputAction: TextInputAction.done,
Please keep in mind that iOS doesn’t support Done on NUMERIC keyboards.
8
I used this way to handle done button in IOS
keyboardType: Platform.isIOS?
TextInputType.numberWithOptions(signed: true, decimal: true)
: TextInputType.number,
// This regex for only amount (price). you can create your own regex based on your requirement
inputFormatters: [FilteringTextInputFormatter.allow(RegExp(r'^\d+\.?\d{0,4}'))],
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