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how can I transform the string "620/100" into "6.2" in a bash script
The context of my question is about image processing. EXIF data are coding the focal length in fractional format, while I need the corresponding decimal string.
Thanks for helping, Olivier
845
While you can't use floating point division in Bash you can use fixed point division. All that you need to do is multiply your integers by a power of 10 and then divide off the integer part and use a modulo operation to get the fractional part. Rounding as needed.
2. Bash arithmetic expansion does not support floating-point arithmetic. When attempting to divide in this case, the output shows zero (0). The result of integer division must be an integer.
$1 means an input argument and -z means non-defined or empty. You're testing whether an input argument to the script was defined when running the script. Follow this answer to receive notifications.
$0 is the name of the script itself (script.sh) $1 is the first argument (filename1) $2 is the second argument (dir1)
Use bc -l
bc -l <<< "scale=2; 620/100"
6.20
OR awk:
awk 'BEGIN{printf "%.2f\n", (620/100)}'
6.20
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