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Flatten DataFrame with multi-index columns

I'd like to convert a Pandas DataFrame that is derived from a pivot table into a row representation as shown below.

This is where I'm at:

import pandas as pd
import numpy as np
df = pd.DataFrame({
    'goods': ['a', 'a', 'b', 'b', 'b'],
    'stock': [5, 10, 30, 40, 10],
    'category': ['c1', 'c2', 'c1', 'c2', 'c1'],
    'date': pd.to_datetime(['2014-01-01', '2014-02-01', '2014-01-06', '2014-02-09', '2014-03-09'])
})
# we don't care about year in this example
df['month'] = df['date'].map(lambda x: x.month)
piv = df.pivot_table(["stock"], "month", ["goods", "category"], aggfunc="sum")
piv = piv.reindex(np.arange(piv.index[0], piv.index[-1] + 1))
piv = piv.ffill(axis=0)
piv = piv.fillna(0)
print piv

which results in

stock            
goods        a       b    
category    c1  c2  c1  c2
month                     
1            5   0  30   0
2            5  10  30  40
3            5  10  10  40

And this is where I want to get to.

goods category month stock
    a       c1     1     5
    a       c1     2     0
    a       c1     3     0
    a       c2     1     0
    a       c2     2    10
    a       c2     3     0
    b       c1     1    30
    b       c1     2     0
    b       c1     3    10
    b       c2     1     0
    b       c2     2    40
    b       c2     3     0

Previously, I used

piv = piv.stack()
piv = piv.reset_index()
print piv

to get rid of the multi-indexes, but this results in this because I pivot now on two columns (["goods", "category"]):

      month category stock    
goods                    a   b
0         1       c1     5  30
1         1       c2     0   0
2         2       c1     5  30
3         2       c2    10  40
4         3       c1     5  10
5         3       c2    10  40

Does anyone know how I can get rid of the multi-index in the column and get the result into a DataFrame of the exemplified format?

like image 202
orange Avatar asked Dec 20 '14 04:12

orange


2 Answers

>>> piv.unstack().reset_index().drop('level_0', axis=1)
   goods category  month   0
0      a       c1      1   5
1      a       c1      2   5
2      a       c1      3   5
3      a       c2      1   0
4      a       c2      2  10
5      a       c2      3  10
6      b       c1      1  30
7      b       c1      2  30
8      b       c1      3  10
9      b       c2      1   0
10     b       c2      2  40
11     b       c2      3  40

then all you need is to change last column name from 0 to stock.

like image 94
behzad.nouri Avatar answered Sep 18 '22 05:09

behzad.nouri


It seems to me that melt (aka unpivot) is very close to what you want to do:

In [11]: pd.melt(piv)
Out[11]:
      NaN goods category  value
0   stock     a       c1      5
1   stock     a       c1      5
2   stock     a       c1      5
3   stock     a       c2      0
4   stock     a       c2     10
5   stock     a       c2     10
6   stock     b       c1     30
7   stock     b       c1     30
8   stock     b       c1     10
9   stock     b       c2      0
10  stock     b       c2     40
11  stock     b       c2     40

There's a rogue column (stock), that appears here that column header is constant in piv. If we drop it first the melt works OOTB:

In [12]: piv.columns = piv.columns.droplevel(0)

In [13]: pd.melt(piv)
Out[13]:
   goods category  value
0      a       c1      5
1      a       c1      5
2      a       c1      5
3      a       c2      0
4      a       c2     10
5      a       c2     10
6      b       c1     30
7      b       c1     30
8      b       c1     10
9      b       c2      0
10     b       c2     40
11     b       c2     40

Edit: The above actually drops the index, you need to make it a column with reset_index:

In [21]: pd.melt(piv.reset_index(), id_vars=['month'], value_name='stock')
Out[21]:
    month goods category  stock
0       1     a       c1      5
1       2     a       c1      5
2       3     a       c1      5
3       1     a       c2      0
4       2     a       c2     10
5       3     a       c2     10
6       1     b       c1     30
7       2     b       c1     30
8       3     b       c1     10
9       1     b       c2      0
10      2     b       c2     40
11      3     b       c2     40
like image 21
Andy Hayden Avatar answered Sep 22 '22 05:09

Andy Hayden